Grouping by JSON array using Underscore JS

Question

I have a JSON array object as follows:

var orders = [{
    orderId: 1,
    firstName: 'John',
    lastName: 'Smith',
    address: {
        street: '123 Main Street',
        city: 'New York',
        zip: 10001
    }
}, {
    orderId: 2,
    firstName: 'John',
    lastName: 'Smith',
    address: {
        street: '456 Main Street',
        city: 'New York',
        zip: 10001
    }
}, {
    orderId: 3,
    firstName: 'John',
    lastName: 'Smith',
    address: {
        street: '123 Main Street',
        city: 'New York',
        zip: 10001
    }
}, {
    orderId: 4,
    firstName: 'John',
    lastName: 'Smith',
    address: {
        street: '123 Main Street',
        city: 'New York',
        zip: 10002
    }
}];

I am trying to use underscore.jsto create a new array object, grouped by address, to match the use case of all orders sent to 123 Main Street, New York, 1001.

Is this the underscore.jsright approach to this? If so, how do I do this? Any hints would be helpful.

Answer 1

Cm. _.groupBy

console.log(_.groupBy(orders, function(obj){
    return obj.address.street + '|' + obj.address.city + '|' + obj.address.zip;
}));

See http://jsfiddle.net/mendesjuan/gc47ruyL/1/

This example assumes that you cannot have |an address, you may need a better delimiter, or use JSON.stringify:

console.log(_.groupBy(orders, function(obj){
    return JSON.stringify([obj.address.street, obj.address.city, obj.address.zip]);
}));

Answer 2

,

var filteredOrders = _.filter(orders, function(order){
  return (order.address.street === '123 Main Street') &&
          (order.address.city === 'New York') &&
          (order.address.zip === 10001);
});

Fiddle