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Make division by zero equal to zero

How can I ignore ZeroDivisionErrorand do n / 0 == 0?

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7 answers

I think that try except(as in the Cyber ​​answer), as a rule, a better way (and more pythonic: it's better to ask for forgiveness than ask permission!), But here's another:

def safe_div(x,y):
    if y == 0:
        return 0
    return x / y

One argument in favor of this, however, is that if you expect it to ZeroDivisionErrorhappen often, checking for 0 denominators will be much faster (this is python 3):

import time

def timing(func):
    def wrap(f):
        time1 = time.time()
        ret = func(f)
        time2 = time.time()
        print('%s function took %0.3f ms' % (f.__name__, int((time2-time1)*1000.0)))
        return ret
    return wrap

def safe_div(x,y):
    if y==0: return 0
    return x/y

def try_div(x,y):
    try: return x/y
    except ZeroDivisionError: return 0

@timing
def test_many_errors(f):
    print("Results for lots of caught errors:")
    for i in range(1000000):
        f(i,0)

@timing
def test_few_errors(f):
    print("Results for no caught errors:")
    for i in range(1000000):
        f(i,1)

test_many_errors(safe_div)
test_many_errors(try_div)
test_few_errors(safe_div)
test_few_errors(try_div)

Conclusion:

Results for lots of caught errors:
safe_div function took 185.000 ms
Results for lots of caught errors:
try_div function took 727.000 ms
Results for no caught errors:
safe_div function took 223.000 ms
Results for no caught errors:
try_div function took 205.000 ms

, try except 3-4 ( , ) ; : 3-4 , . , if, (10% ), ( , ) .

+5

, . , , , .

def weird_division(n, d):
    return n / d if d else 0
+18

try/except.

def foo(x,y):
    try:
        return x/y
    except ZeroDivisionError:
        return 0

>>> foo(5,0)
0

>>> foo(6,2)
3.0
+11
def foo(x, y):
    return 0 if y == 0 else x / y
+4

(https://docs.python.org/2/library/operator.html), , . , y 0 0 x/y .

0

, Zer0DivErrr, , try-except. - , , :

(if Y Z=X/Y else Z=0)
0

:

x=0,y=0
print (y/(x or not x))

:

>>>x=0
>>>y=0
>>>print(y/(x or not x))
0.0
>>>x =1000
>>>print(y/(x or not x))
0.000999000999000999

not x false, x 0, x.

0

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