Say I have a function like this:
{-
class C a where
foo :: forall f a b. (C (f a), C (f b)) => f a -> f b
foo = _
Now, if I wanted to move the area aand bto the right of the type of restrictions typeclass in the type foo(for example, because I want to use foofor the implementation of the method typeclass, to be polymorphic in aand b), it can be done with a bit of work with Data.Constraint.Forall:
{-
{-
import Data.Constraint
import Data.Constraint.Forall
foo' :: forall f. (ForallF C f) => forall a b. f a -> f b
foo' = helper
where
helper :: forall a b. f a -> f b
helper = case (instF :: ForallF C f :- C (f a)) of
Sub Dict -> case (instF :: ForallF C f :- C (f b)) of
Sub Dict -> foo
Now, my question is, suppose I change my function to something related to types:
{-
type family F a :: * -> *
bar :: forall f g a b. (F (f a) ~ g a, F (f b) ~ g b) => f a -> f b
bar = _
Is there a way to adapt the technique described above?
Here is what I tried:
{-
{-
import Data.Constraint
import Data.Constraint.Forall
type F'Eq f g x = F (f x) ~ g x
bar' :: forall f g. (Forall (F'Eq f g)) => forall a b. f a -> f b
bar' = helper
where
helper :: forall a b. f a -> f b
helper = case (inst :: Forall (F'Eq f g) :- F'Eq f g a) of
Sub Dict -> case (inst :: Forall (F'Eq f g) :- F'Eq f g b) of
Sub Dict -> bar
But (unsurprisingly) this fails due to the synonym for the unsaturated type:
A type synonym ‘F'Eq’must have 3 arguments, but given 2
In an expression type signature: Forall (F'Eq f g) :- F'Eq f g a
In the expression: (inst :: Forall (F'Eq f g) :- F'Eq f g a)