There is no corresponding function to call 'regex_search (...)'

Question

Given the pointer and the length of the old style const char *, is there a way to invoke std::regex_search()on it without first copying the contents of the buffer to std::string? Here is a simple example of a problem:

#include <regex>

int main()
{
    const char *text = "123 foobar 456";
    const size_t len = strlen(text);

    const std::regex rx(" (.+)bar");

    std::smatch what;
    std::regex_search( text, text+len, what, rx); // <- problematic line

    return 0;
}

I thought the 5th std :: regex_search () , which takes up two iterators, is what I need, but I don’t quite understand how to convert pointers to iterators. When I try to compile the above code, I get the following:

g++ -std=c++11 test.cpp
test.cpp:11:45: error: no matching function for call to ‘regex_search(const char*&, const char*, std::smatch&, const regex&)’
/usr/include/c++/4.9/bits/regex.h:2131:5: note: template<class _Bi_iter, class _Alloc, class _Ch_type, class _Rx_traits> bool std::regex_search(_Bi_iter, _Bi_iter, std::match_results<_BiIter, _Alloc>&, const std::basic_regex<_CharT, _TraitsT>&, std::regex_constants::match_flag_type)
 regex_search(_Bi_iter __s, _Bi_iter __e,

... and many more mistakes!

Can it const char *be converted to the desired iterator? Did I do it wrong? I don’t understand how it works?

Answer 1

, match_results. smatch , std::string, std::string::iterator regex. raw char const *, cmatch.

std::smatch what;

std::cmatch what;