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Why is a higher match template not selected?

I have the following xml:

<root xmlns:s="http://example.com/schema">
  <foo>
     <s:bars>
       <s:bar name="normal">bar101</s:bar>
       <s:bar name="special">Foobar</s:bar>
       <s:bar name="super">FuBar</s:bar>
     </s:bars>
  </foo>
</root>

I use the following xslt template to output elements bar:

  <xsl:template match="root">
    <foos>
      <xsl:apply-templates select="foo/s:bars"/>
    </foos>
  </xsl:template>

  <xsl:template match="s:bars/s:bar[@name='special' or @name='super']">
    <xsl:element name="{@name}">
      <xsl:text>special value:</xsl:text>
      <xsl:value-of select="."/>
    </xsl:element>
  </xsl:template>

  <xsl:template match="s:bars/s:bar">
    <xsl:element name="{@name}">
      <xsl:value-of select="."/>
    </xsl:element>
  </xsl:template>

Oddly enough, this outputs the following xml when using the .NET XSLT processor:

<foos>
  <normal>bar101</normal>
  <special>Foobar</special>
  <super>FuBar</super>
</foos>

Apparently, the template for is s:bars/s:bar[@name='special' or @name='super']not used. I was expecting the following output:

<foos>
  <normal>bar101</normal>
  <special>special value:Foobar</special>
  <super>special value:FuBar</super>
</foos>

I tried adding an extra template to select bars

  <xsl:template match="s:bars">
    <xsl:comment>bars</xsl:comment>
    <xsl:apply-templates />
  </xsl:template>

but this did not change the result (but added <!--bars-->to the result to invoke the template.)

It seems that I expect something different from the rules of the template or misunderstanding them. Should the attributes of the AND element be matched by coincidence on the ONLY element?

XSLT-, .Net XSLT-?

+4
1

0.5 (. http://www.w3.org/TR/xslt#conflict), XSLT , . , XSLT- . , (, <xsl:template match="s:bars/s:bar[@name='special' or @name='super']" priority="5">) , .

+2

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