Rabbitmq Ack or Nack, leaving messages in the queue

Question

I played with RabbitMq.net and message confirmations. If the consumer can process the message, you can send back ack in the form

channel.BasicAck(ea.DeliveryTag, false);

which will get him out of line.

But what about whether it is impossible to process the message? perhaps a temporary outage, and you don’t want the message removed from the queue to be simply inserted in the back and continued from the next message?

I tried using

channel.BasicNack(ea.DeliveryTag, false, true);

but next time he will still receive the same message and will not go to the next message in the queue

my full code

class Program
{
    private static IModel channel;
    private static QueueingBasicConsumer consumer;
    private static IConnection Connection;

    static void Main(string[] args)
    {
        Connection = GetRabbitMqConnection();
        channel = Connection.CreateModel();
        channel.BasicQos(0, 1, false);
        consumer = new QueueingBasicConsumer(channel);
        channel.BasicConsume("SMSQueue", false, consumer);
        while (true)
        {
            if (!channel.IsOpen)
            {
                throw new Exception("Channel is closed");
            }
            var ea = consumer.Queue.Dequeue();
            string jsonified = Encoding.UTF8.GetString(ea.Body);
            var message = JsonConvert.DeserializeObject<SmsRecords>(jsonified);
            if (ProcessMessage())
                channel.BasicAck(ea.DeliveryTag, false);
            else
                channel.BasicNack(ea.DeliveryTag, false, true);
        }
    }

    private static bool ProcessMessage()
    {
        return false;
    }

    public static IConnection GetRabbitMqConnection()
    {
        try
        {
            var connectionFactory = new ConnectionFactory
            {
                UserName = "guest",
                Password = "guest",
                HostName = "localhost"
            };
            return connectionFactory.CreateConnection();
        }
        catch (Exception ex)
        {
            Console.WriteLine(ex.Message);
            return null;
        }
    }
}

Answer 1

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