How to match multiple addresses in sed?

Question

I want to execute a command sedfor any line that matches either andone or orseveral commands: for example, it sed '50,70/abc/d'will delete all lines in the range 50,70that match /abc/, or a way to do sed -e '10,20s/complicated/regex/' -e '30,40s/complicated/regex/without re-enterings/compicated/regex/

Answer 1

logical and

The part andcan be done using curly braces:

sed '50,70{/abc/d;}'

In addition, braces can be nested in several conditions and.

(The above was tested at GNU sed. BSD sedmay differ in small but disappointing details.)

Logical or

or :

sed -e '10,20{b cr;}' -e '30,40{b cr;}' -e b -e :cr -e 's/complicated/regex/' file

• 10,20{b cr;}

  10 20 cr

• 30,40{b cr;}

  30 40 cr

• b

  .

• :cr

  cr

• s/complicated/regex/

  , cr.

GNU sed :

sed '10,20{b cr}; 30,40{b cr}; b; :cr; s/complicated/regex/' file

Answer 2

10 20 30 40, GNU:

sed -e '10,20bA;30,40bA;b;:A;s/complicated/regex/;d' file

sed -e '10,20bA' -e '30,40bA' -e 'b;:A;s/complicated/regex/;d' file

---

bA: :A

b: → script

d:

Answer 3

, sed , - awk, - :

awk 'NR >= 50 && NR <= 70 && /abc/ {next} {print}' inputFile
awk '(NR >= 10 and NR <= 20) || (NR >= 30 && NR <= 40) {
     sub("from-regex", "to-string", $0); print }'

Answer 4

sed is great for simple substitutions on separate lines, but for something else just use awk for clarity, reliability, portability, maintainability, etc.

awk '
(NR>=50 && NR<=70) && /abc/ { next }
(NR>=10 && NR<=20) || (NR>=30 && NR<=40) { sub(/complicated/,"regex") }
{ print }
' file