Gulp.js - unable to copy generated files from one folder to another

Question

gulp.task('minify-css', function () {

   gulp.src(['src/test/test.css])
   .pipe(concat('test1.css'))
   .pipe(minifyCSS())
   .pipe(gulp.dest('src/source/'))
   .pipe(filesize())

});
gulp.task('copy-css',['minify-css'], function () {

   gulp.src('src/source/*.css')
   .pipe(gulp.dest('src/dest/'));

});

It seems like the first time I run 'gulp copy-css'

Starting 'minify-css'...
[18:54:39] Finished 'minify-css' after 61 ms
[18:54:39] Starting 'copy-css'...
[18:54:39] Finished 'copy-css' after 1.86 ms

but the copy operation is not performed, probably because it is performed before the file to be copied is not generated

Despite the fact that I mentioned minify-css as a dependency for the copy-css task, it does not seem to conform to this convention in this case.

When gulp copy-css is run again, this time the file is copied because the file has already been created from a previously executed command. But this can exceed the goal when the code is used in production.

Answer 1

change both tasks below

gulp.task('minify-css', function () {
    return  gulp.src(['src/test/test.css])
   .pipe(concat('test1.css'))
   .pipe(minifyCSS())
   .pipe(gulp.dest('src/source/'))
   .pipe(filesize())    
});

gulp.task('copy-css',['minify-css'], function () {
   return gulp.src('src/source/*.css')
   .pipe(gulp.dest('src/dest/'));

});

return, , copy-css minify-css. , ...

Answer 2

question, , , return gulp.src(['src/test/test.css])...

Answer 3

on('finish'):

gulp.task('minify-css', function (cb) {

   gulp.src(['src/test/test.css'])
    .pipe(concat('test1.css'))
    .pipe(minifyCSS())
    .pipe(gulp.dest('src/source/'))
    .pipe(filesize())
    .on('finish', function() {
        // All tasks should now be done
        return cb();
    })

});

gulp.task('copy-css',['minify-css'], function () {

   gulp.src('src/source/*.css')
     .pipe(gulp.dest('src/dest/'));

});

PS: gulp.src , ' gulp.src(['src/test/test.css])