Is every lambda function an anonymous class?

Question

auto a = [](){};
auto b = [](){};
vector<decltype(a)> v;
v.push_back(a); //ok
v.push_back(b); //compiler error

a and b are of a different type.

I am wondering if each lambda function is really a kind of anonymous class, whenever we create a lambda function, we create a new class with a random name that is visible only to the compiler?

Answer 1

Yes, each lambda introduces its own unique type.

Now the same lambda can have several closures (lambda instances) associated with it in several ways. C ++ 14 type output returns the simplest:

auto nothing() {
  return []{};
}

, . , - .