How to get full dict with max value of shared key in dicts list

Question

I have a list of dicts as below:

lod = [
{'name': 'Tom', 'score': 60},
{'name': 'Tim', 'score': 70},
{'name': 'Tam', 'score': 80},
{'name': 'Tem', 'score': 90}
]

I want to get {'name': 'Tem', 'score':90}, but I can only do below:

max(x['score'] for x in lod)

This returns the value 90.

How can i get the whole dict?

Answer 1

You can use a key function max :

>>> lod = [
... {'name': 'Tom', 'score': 60},
... {'name': 'Tim', 'score': 70},
... {'name': 'Tam', 'score': 80},
... {'name': 'Tem', 'score': 90}
... ]
... 
>>> max(lod, key=lambda x: x['score'])
{'name': 'Tem', 'score': 90}

Answer 2

Just pass a list max, for example:

>>> from operator import itemgetter
>>> lod = [
... {'name': 'Tom', 'score': 60},
... {'name': 'Tim', 'score': 70},
... {'name': 'Tam', 'score': 80},
... {'name': 'Tem', 'score': 90}
... ]
>>> max(lod, key=itemgetter('score'))
{'score': 90, 'name': 'Tem'}

Answer 3

I do not know how long it takes sorting,

>>>sorted(lod, key=lambda x:x['score'])[-1]
{'name': 'Tem', 'score': 90}