How to find max and min from string in python?

Question

This is my current program. It displays the wrong max and min. What is missing in my if statement?

def palin():
  max = 0
  min = 50
  numbers = "23","3","4","6","10"
  for x in numbers:

    if x>max:
      max=x
    if x<min:
      min=x

  print max
  print min

Answer 1

When you perform a string comparison or attempting to use min(), max()string, you actually maintain alphabetical order:

>>> sorted(numbers)
['10', '23', '3', '4', '6']

This is why many of Python 's built-in functions that rely on support for positional comparison : key

>>> numbers
('23', '3', '4', '6', '10')
>>> sorted(numbers, key=int)
['3', '4', '6', '10', '23']
>>> min(numbers, key=int)
'3'
>>> max(numbers, key=int)
'23'

Answer 2

Your numbers are strings. First convert them to integers:

numbers = [int(num) for num in numbers]

---

def palin():
  max = 0
  min = 50
  numbers = "23","3","4","6","10"
  numbers = [int(num) for num in numbers]
  for x in numbers:

    if x>max:
      max=x
    if x<min:
      min=x

  print max
  print min

Answer 3

python built-in /.

max() min() .

str_numbers = ("23", "3", "4", "6", "10")
numbers = [int(n) for n in str_numbers ]  # convert to integers
max_value = max(numbers)
min_value = min(numbers)

max() min() , :

str_numbers = ("23", "3", "4", "6", "10")
max_value = max(int(n) for n in str_numbers)
min_value = min(int(n) for n in str_numbers)

Answer 4

If you installed Numpy, you can easily get the result.

import numpy as np

numbers = ["23","3","4","6","10"]
numbers = [int(n) for n in numbers]
numpy_array = np.array(numbers)
print 'Max:  ', numpy_array.max()
print 'Min:  ', numpy_array.min()
print 'Mean: ', numpy_array.mean()