I am trying to decompose the expression and divide the coefficients into matrix forms so that:

Closely related to Expression of factor factor for matrix coefficients? where Wild symbols are used with match(form)to determine the coefficients for its matrix form. However, I cannot get the method match(form)to work for the following.
Why does match(form)method fail?
What are the net alternatives to achieve this?
v_1, theta_1, v_2, theta_2, x, L = symbols("v_1, theta_1, v_2, theta_2, x, L")
a_1, a_2, a_3, a_4 = symbols("a_1, a_2, a_3, a_4", real=True)
V = a_1*x**0 + a_2*x**1 + a_3*x**2 + a_4*x**3
shape_coeffs = solve([Eq(v_1, V.subs({x:0})),
Eq(theta_1, V.diff(x).subs({x:0})),
Eq(v_2, V.subs({x:L})),
Eq(theta_2, V.diff(x).subs({x:L}))],
(a_1, a_2, a_3, a_4))
V = V.subs(shape_coeffs)
V = sympy.collect(sympy.expand(V), (v_1, theta_1, v_2, theta_2))

And collect terms until the shape of the matrix becomes apparent. To match the forms:
C_1, C_2, C_3, C_4 = symbols("C_1, C_2, C_3, C_4", cls=Wild)
form = c_1*v_1 + c_2*theta_1 + c_3*v_2 + c_4*theta_2
mat_coeffs = V.match(form)
N = Matrix([C_1, C_2, C_3, C_4]).transpose()
N = N.subs(mat_coeffs)
v = Matrix([v_1, theta_1, v_2, theta_2])

Unlike the question mentioned, V.match(form)returns No instead of the dict () containing {C_1:f(x), C_2:f(x), C_3:f(x), C_4:f(x)}. Why is this failing? - upon examination, the solution is obvious.