.
select u.userid, u.username, s.salary
from users u left join (select distinct userid, salary from salaries) s
on u.userid = s.userid
. s ( pluralis.) .
, a GROUP BY:
select u.userid, u.username, max(s.salary)
from users u left join salaries s
on u.userid = s.userid
group by u.userid, u.username
, :
select u.userid, u.username, (select max(s.salary) from salaries s
where u.userid = s.userid)
from users