Firstly, for this question it is better to use the general values of 24 and 53. The fact that the leading bit is not represented is only an aspect of coding.
, log2 (10) ( 3,32) . , 4 , , 3.32 .
53 /log 2 (10) → 15.95 (16- )
24 /log 2 (10) → 7,22 (7- )
, , . , , , , , , , , . , "6... 9" "15... 17". 6 - , 32, 9 - , ..
Exploring Binary . - , , log2 (10) = 3.32.