First you need to get the diff date until last Friday:
var now = new Date(),
day = now.getDay();
Depending on what “last Friday” means to you, use the following
next friday
var diff = (day <= 5) ? (7 - 5 + day ) : (day - 5);
if today is Friday, then come back today, otherwise the nearest last Friday
var diff = (7 - 5 + day) % 7;
var diff = 7 - 5 + day;
setDate. setDate , :
mdn:
dayValue , setDate() Date. , 0 dayValue, .
var date = new Date();
date.setDate(now.getDate() - diff);
date.setHours(0);
date.setMinutes(0);
date.setSeconds(0);
var friday = date.getTime();
function getLastFridayOf(date) {
var d = new Date(date),
day = d.getDay(),
diff = (day <= 5) ? (7 - 5 + day ) : (day - 5);
d.setDate(d.getDate() - diff);
d.setHours(0);
d.setMinutes(0);
d.setSeconds(0);
return d.getTime();
}
, JS .
new Date(getLastFridayOf('2015-05-01')).toDateString()
-> Fri Apr 24 2015
new Date(getLastFridayOf('2015-05-19')).toDateString()
-> Fri May 15 2015
new Date(getLastFridayOf('2015-05-16')).toDateString()
-> Fri May 15 2015
new Date(getLastFridayOf('2015-05-15')).toDateString()
-> Fri May 08 2015