I am loading my content from mine DBusing PHPin my div.
I have dropdownover it where I should be able to sort the content, which means that when I select the dropdownold content in it divis deleted, and the new one appears.
So, how can you βdeleteβ old content in divand get new content based on dropdown selection?
This is what I got so far:
<div class="col-md-4">
<ul class="nav nav-tabs top_nav">
<li role="presentation" class="active"><a href="#">Edit</a></li>
<li role="presentation" class="inactive">
<select id="filter_type">
<option selected value="Alle">Alle</option>
<option value="Privat_Tale">Privat Tale</option>
<option value="Erhverv_Tale">Erhverv Tale</option>
<option value="Gamle">Gamle</option>
<option value="Privat_MBB">Privat MBB</option>
<option value="Erhverv_MBB">Erhverv MBB</option>
<option value="Familietele">Familietele</option>
<option value="Retention">Retention</option>
</select>
</li>
</ul>
<div class="abo_load" id="abo_load">
<?php
if (mysql_num_rows($sql_select_edit) > 0) {
while ($row = mysql_fetch_assoc($sql_select_edit)) {
?>
<div class="abo_box" id="abo_box">
<label class="abo_navn"><?php echo $row['abo_name']; ?></label>
<input type="hidden" value="<?php echo $row['category']; ?>" name="category" />
<form action="conn/delete.php" method="post">
<input type="hidden" value="<?php echo $row['id'];
?>" name="slet">
<input class="delete" value="Delete" type="submit" onclick="return confirm('Er du sikker??\nDet ville jo vΓ¦re ΓV med en Fejl 40!');">
</form>
<label class="edit">Edit</label>
<?php include("files/edit_list_content.php"); ?>
</div>
<?php
}
}
?>
</div>
</div>
EDIT:
JQuery, php, , . , JQuery . , JQuery. , , php , , , JQuery. , php