Practical use
function largestInList(list) {
var largest = Number.MIN_VALUE;
for (var i = 0; i < list.length; i++) {
if (largest <= list[i])
largest = list[i];
}
return largest;
}
My Tests
it("Return the largest in a list", function() {
expect(largestInList).toBeDefined();
expect(largestInList([])).toEqual(Number.MIN_VALUE);
expect(largestInList([-11])).toEqual(-11);
expect(largestInList([-1, -3])).toEqual(-1);
expect(largestInList([3, -1])).toEqual(3);
expect(largestInList([3, -1, 8])).toEqual(8);
expect(largestInList([4, 9, -1, 9, 8])).toEqual(9);
expect(largestInList([3, 61, 8])).toEqual(61);
expect(largestInList([3, 61, 8, 333, -1])).toEqual(333);
});
source
share