I have two OrderedSets, and I'm trying to check if one of the subsets of the other is both the elements and their order are important. However, the orderedset package gives me weird results.
>>> import orderedset
>>> a = orderedset.OrderedSet([433, 316, 259])
>>> b = orderedset.OrderedSet([433, 316, 69])
>>> a.issuperset(b)
True
This doesn't make any sense to me because it bcontains a value ( 69) that is definitely not in a. Why aa supersetof b, then?
However, when I try to do this:
>>> c = orderedset.OrderedSet([1, 2, 3])
>>> d = orderedset.OrderedSet([1, 2, 4])
>>> c.issuperset(d)
False
This behavior seems inconsistent to me: why does the choice of [433, 316, 259]versus values [1, 2, 3]in the OrderedSet affect the output issuperset()?
Perhaps there is a better way to do this? I need to know if elements are in bin ain the same order. This means that if
a = OrderedSet([433, 316, 259])
, , a (433). , :
OrderedSet([433, 316, 259])
OrderedSet([433, 316]])
OrderedSet([433])
:
OrderedSet([433, 259])
OrderedSet([316, 259])
OrderedSet([433, 316, 69])
OrderedSet([433, 259, 316])
OrderedSet([259, 433])
...
, - , , .