Assuming I have a function like
foo = 8 + f1 where f1 = 8 + 9 f2 = 8 + 10
f1clearly need to be appreciated, but f2not necessary. So will it be? I see how evaluating each expression wherewill be a performance issue.
f1
f2
where
Yes, he is lazy, so he f2will not be evaluated, for example:
foo = 8 + f1 where f1 = 8 + 9 f2 = last [1..]
will be calculated instantly and will forever remain if it is strict.