Int can be doubled

Question

This code seems to work in Java, breaking everything that I thought about knowing the language:

int x = 0;
x += 7.4;

x now has the value 7. Of course, you can't just write int x = 7.4 , so this behavior seems strange and inconsistent to me.

Why did the Java developers choose this behavior?

The question that mine was marked as a duplicate actually answered the question "what is happening", but not my main question: what is the rationale.

+4

Brrch Aug 24 '15 at 10:42

4 answers

- X = (int) (x + 7.4)

+1

SacJn 24 . '15 10:43

. . .

int long float double - . IEEE 754, (§4.2.4).

+1

In my opinion x = 7 due to basic conversion

0

user5210134 Aug 24 '15 at 16:39

Jens Schauder · Accepted Answer · 2015-08-24T10:44:27+0000

The operators for numbers perform all kinds of castings, which in this case convert 7.4 double to 7 int by rounding it.

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x= (int)(x + 7.4)

x - int, 7.4 x double vs Binary Numeric Promotion, 7.4 .

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