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SQL Delete a string between two characters

I have a line such as:

`a|b^c|d|e^f|g`

and I want to maintain the distinction of pipelines, but to remove morphing with carrots, keeping only the first value of this sub-boundary.

The output will be:

`a|b|d|e|g`

Is there a way to do this with a simple SQL function?

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3 answers

Another option using CHARINDEX, REPLACEand SUBSTRING:

DECLARE @OriginalString varchar(50) = 'a|b^c^d^e|f|g'

DECLARE @MyString varchar(50) = @OriginalString 

WHILE CHARINDEX('^', @MyString) > 0 
BEGIN
    SELECT @MyString = REPLACE(@MyString, 
                               SUBSTRING(@MyString, 
                                         CHARINDEX('^', @MyString), 
                                         CASE WHEN CHARINDEX('|', @MyString, CHARINDEX('^', @MyString)) > 0 THEN
                                            CHARINDEX('|', @MyString, CHARINDEX('^', @MyString)) - CHARINDEX('^', @MyString)
                                         ELSE
                                            LEN(@MyString)
                                         END
                                         )
                       , '')
END

SELECT @OriginalString As Original, @MyString As Final

Output:

Original              Final
a|b^c^d^e|f|g         a|b|f|g
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( ). , ..

case
    when charindex('^', s) > 0
    then stuff(
             s,
             charindex('^', s),
             charindex('|', s + '|', charindex('^', s) + 1) - charindex('^', s),
             ''
         )
    else s
end

, :

declare @s varchar(30) = 'a|b^c^d|e|f^g|h^i';
declare @n int = charindex('^', @s);

while @n > 0
begin
    set @s = stuff(@s, @n, charindex('|', @s + '|', @n + 1) - @n, '');
    set @n = charindex('^', @s, @n + 1);
end
select @s;

, . , .

+2

, |, ,

SELECT Cast(left(intr,len(intr)-1) AS VARCHAR(1000)) AS res
FROM   (SELECT LEFT(split_val, Isnull(NULLIF(Charindex('^', split_val), 0)-1, Len(split_val))) + '|'
        FROM   Udf_splitstring('a|bdd^c|d|e^f|g', '|')
        FOR xml path (''))a (intr)

: a|bdd|d|e|g

-

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