DataTable with Dropdown Column

Question

I need to create a drop-down list in a column in a DataTable jQuery, as it now looks below:

And I want it to be as shown below.

and the code that I use

<table id="example" class="hover row-border dataTable" role="grid" width="100%">
    <thead class="dataTableHeader">
        <tr>
            <th>Days</th>
            <th>Start Time</th>
            <th>End Time</th>
        </tr>
    </thead>
</table>

$(document).ready(function () {
    $('#example').DataTable({
        "aaData": OrganizationData.OrganizationPreference.ScheduleDaysCol,
        "columns": [
            {"data": "DayName"},
            {"data": "StartDateHour"},
            {"data": "EndDateHour"}

        ],
        "paging": false,
        "ordering": false,
        "info": false,
        "filter": false
    });
});

Answer 1

Another way would be to use a method render:

        "render": function(d,t,r){
            var $select = $("<select></select>", {
                "id": r[0]+"start",
                "value": d
            });
            $.each(times, function(k,v){
                var $option = $("<option></option>", {
                    "text": v,
                    "value": v
                });
                if(d === v){
                    $option.attr("selected", "selected")
                }
                $select.append($option);
            });
            return $select.prop("outerHTML");
        }

Job example .

Answer 2

DataTables has an editor for this type of thing, as agreed upon by Samyukta and others: https://editor.datatables.net/examples/inline-editing/simple

, . , , .

jquery , :

//utility functions to get half-hour increment lists
function getTimeList(){
    var iterations = 48;
    var result = [];
    for(int i = 0; i < iterations; i++){
        var hour = Math.floor(i / 2);
        var minute = (i % 2) > 0 ? '30' : '00';
        result.push(hour + ':' + minute);
    }
    return result;
}

function getOptionTimeList(){
    var raw = getTimeList();
    var iterations = raw.length;
    var result = '';
    for(int i = 0; i < iterations; i++){
        result = result + '<option>' + raw[i] + '</option>';
    }
    return result;
}


//I'm using the not selector to avoid changing the days into dropdown by accident
$('#example tbody tr td:not(#example tbody tr:first-child)').each(
    function(index, element){
        var value = element.innerHTML;
        var optionList = getOptionTimeList();
        var replacement = '<td><select>' + optionList + '</select></td>';


        $(element).replaceWith(replacement)
    }
);

, . , .

Answer 3

 "aaData": OrganizationData.OrganizationPreference.ScheduleDaysCol,
                        "columnDefs": [{ "targets": 0,"data": "DayName" },
                            {
                            "targets": 1,
                            "data": "StartDateTime",
                           "render": function (data, type, full, meta) {
                                    var $select = $("<select></select>", {
                                    });
                                    $.each(times, function (k, v) {

                                        var $option = $("<option></option>", {
                                            "text": v,
                                            "value": v
                                        });
                                        if (data === v) {
                                            $option.attr("selected", "selected")
                                        }
                                        $select.append($option);
                                    });
                                    return $select.prop("outerHTML");
                            }