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How to find the union of two lines and maintain order

I have two lines, and I would like to find their union. In doing so, I would like to maintain order. My goal is that I am trying several ways to recognize an image and get different results. I would like to combine all the different results into one result that will have the most content.

This is at least what I need:

#example1
string1 = "This is a test trees are green roses are red"
string2 = "This iS a TEST trees 12.48.1952 anthony gonzalez"
finalstring = "this is a test trees are green roses are red 12.48.1952 anthony gonzalez" 

#example2
string2 = "This is a test trees are green roses are red"
string1 = "This iS a TEST trees 12.48.1952 anthony gonzalez"
finalstring = "this is a test trees are green roses are red 12.48.1952 anthony gonzalez"

#example3
string1 = "telephone conversation in some place big image on screen"
String2 = "roses are red telephone conversation in some place big image on screen"
finalstring = "roses are red telephone conversation in some place big image on screen"
#or the following - both are fine in this scenario.
finalstring = "telephone conversation in some place big image on screen roses are red "

Here is what I tried:

>>> string1 = "This is a test trees are green roses are red"
>>> string2 = "This iS a TEST trees 12.48.1952 anthony gonzalez"
>>> list1 = string1.split(" ")
>>> list2 = string2.split(" ")
>>> " ".join(list(set(list1) | set(list2))).lower()
'a gonzalez this is trees anthony roses green are test 12.48.1952 test is red'
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3 answers

You can use difflib.SequenceMatcherfor this:

import difflib
def merge (l, r):
    m = difflib.SequenceMatcher(None, l, r)
    for o, i1, i2, j1, j2 in m.get_opcodes():
        if o == 'equal':
            yield l[i1:i2]
        elif o == 'delete':
            yield l[i1:i2]
        elif o == 'insert':
            yield r[j1:j2]
        elif o == 'replace':
            yield l[i1:i2]
            yield r[j1:j2]

Used as follows:

>>> string1 = 'This is a test trees are green roses are red'
>>> string2 = 'This iS a TEST trees 12.48.1952 anthony gonzalez'

>>> merged = merge(string1.lower().split(), string2.lower().split())
>>> ' '.join(' '.join(x) for x in merged)
'this is a test trees are green roses are red 12.48.1952 anthony gonzalez'

, ( ):

>>> merged = merge(string1.lower(), string2.lower())
>>> ''.join(merged)
'this is a test trees 12.48.1952 arenthony gronzaleen roses are redz'

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. , , , , set() .

string1 = "This is a test trees are green roses are red"
string2 = "This iS a TEST trees 12.48.1952 anthony gonzalez"

str_lst = string1.split()

for s, t in zip(string1.split(), string2.split()):
    if s.lower() == t.lower():
        continue
    else:
        str_lst.append(t)

string = " ".join(s.lower() for s in str_lst)
#this is a test trees are green roses are red 12.48.1952 anthony gonzalez
+1
" ".join(x if i >= len(string2.split()) or x == string2.lower().split()[i] else " ".join((x, string2.split()[i])) for i, x in enumerate(string1.lower().split()))

You can use the understanding of the generator and joinhow it is to accomplish what you want. This sets ito the word index in string1and xto this word. It then checks to see if it is a word string2, and if not, adds the word in string2in iin xin order to put the two words in the final string.

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