Question: How can I process a form using jQuery and a $ .ajax request so that the data is passed to a script that writes it to the database?
Problem: I have a simple email registration form that, when processing, adds an email along with the current date to a table in the MySQL database. Processing a form without jQuery works as intended, adding an email address and a date. Using jQuery, the form submits successfully and returns a success message. However, no data is added to the database.
Any understanding would be greatly appreciated!
<?php <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Sample</title> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ </script> <style type="text/css"> #email { margin-right:2px; padding:5px; width:145px; border-top:1px solid #ccc; border-left:1px solid #ccc; border-right:1px solid #eee; border-bottom:1px solid #eee; font-size:14px; color:#9e9e9e; } #signup-success { margin-bottom:20px; padding-bottom:10px; background:url(../img/css/divider-dots.gif) repeat-x 0 100%; display:none; } #signup-success p, #signup-success-nojs { padding:5px; background:#fff; border:1px solid #dedede; text-align:center; font-weight:bold; color:#3d7da5; } </style> </head> <body> <?php include('process.php'); ?> <form id="newsletter" class="divider" name="newsletter" method="post" action=""> <fieldset> <input id="email" type="text" name="email" /> <input id="submit-button" type="image" src="<?php echo $base_url; ?>/assets/img/css/signup.gif" alt=" SIGNUP " /> <input id="submitted" type="hidden" name="submitted" value="true" /> </fieldset> </form> <div id="signup-success"><p>You have successfully subscribed!</p></div> </body> </html>
Frustrateduser
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