Python equivalent equivalent

Question

I have a dictionary.

dict = { 'a' : 'b', 'c' : 'd' } 

In php, I would like something like implode (',', $ dict) and get the output of 'a, b, c, d' How to do this in python?

Answer 1

This seems the easiest way:

 >>> from itertools import chain >>> a = dict(a='b', c='d') >>> ','.join(chain(*a.items())) 'a,b,c,d' 

Answer 2

Firstly, the answer is incorrect :

 ','.join('%s,%s' % i for i in D.iteritems()) 

This answer is incorrect because, although associative arrays in PHP have this order, dictionaries in Python do not. The way to compensate for this is to either use an ordered display type (e.g. OrderedDict ), or force an explicit order to be set:

 ','.join('%s,%s' % (k, D[k]) for k in ('a', 'c')) 

Answer 3

Use the join string in a flattened list of dictionary items, for example:

 ",".join(i for p in dict.items() for i in p) 

Also, you probably want to use OrderedDict .

Answer 4

This has quadratic performance, but if the dictionary is always small, it may not matter to you.

 >>> sum({'a':'b','c':'d'}.items(), ()) ('a', 'b', 'c', 'd') 

note that dict.items () does not preserve order, so ('c', 'd', 'a', 'b') will also be a possible output

Answer 5

 a=[] [ a.extend([i,j]) for i,j in dict.items() ] 

Answer 6

Or

 [value for pair in {"a": "b", "c" : "d"}.iteritems() for value in pair] 

or

 (lambda mydict: [value for pair in mydict.iteritems() for value in pair])({"a": "b", "c" : "d"}) 

Explanation:

Simplified this example returns each value from each pair in mydict

Edit: also add “,” around them. join (). I did not read your question correctly.

Answer 7

I know this is an old question, but it should also be noted.

The original question is misleading. implode () does not smooth an associative array in PHP, it combines values

 echo implode(",", array("a" => "b", "c" => "d")) // outputs b,d 

implode () will be the same as

 ",".join(dict.values()) # outputs b,d 

Answer 8

This is not very elegant, but it works:

 result=list() for ind in g: result.append(ind) for cval in g[ind]: result.append(cval) 

Answer 9

dictList = dict.items ()

This will return a list of all items.