Play sound byte [] in C #

Question

I understand that you can use SoundPlayer to play sound in C #; however, I want to be able to play sound using the OS-default sound player using this method from the sound represented in the byte array. Is it possible?

Answer 1

Opening any file using an application, for example. media player, file required.

Thus, you need to save the byte array to a file in some format, for example. WAV and open it:

 byte[] bytes = ... string name = Path.ChangeExtension(Path.GetRandomFileName(), ".wav"); string path = Path.Combine(Path.GetTempPath(), name); File.WriteAllBytes(path, bytes); Process.Start(path); 

This code will open the default user media player, just as you clicked it in Windows Explorer.

Answer 2

The SoundPlayer constructor accepts a Stream for playback. You can get the stream from byte [] by creating a MemoryStream.

Answer 3

abatishchev has a good answer, but you don't need to save bytes to a file and then play the file. you can write these bytes to a MemoryStream and then play a MemoryStream, as this method does:

 using System; using System.Collections.Generic; using System.IO; using System.Linq; using System.Windows.Forms; public static void PlayBeep(UInt16 frequency, int msDuration, UInt16 volume = 16383) { var mStrm = new MemoryStream(); BinaryWriter writer = new BinaryWriter(mStrm); const double TAU = 2 * Math.PI; int formatChunkSize = 16; int headerSize = 8; short formatType = 1; short tracks = 1; int samplesPerSecond = 44100; short bitsPerSample = 16; short frameSize = (short)(tracks * ((bitsPerSample + 7) / 8)); int bytesPerSecond = samplesPerSecond * frameSize; int waveSize = 4; int samples = (int)((decimal)samplesPerSecond * msDuration / 1000); int dataChunkSize = samples * frameSize; int fileSize = waveSize + headerSize + formatChunkSize + headerSize + dataChunkSize; // var encoding = new System.Text.UTF8Encoding(); writer.Write(0x46464952); // = encoding.GetBytes("RIFF") writer.Write(fileSize); writer.Write(0x45564157); // = encoding.GetBytes("WAVE") writer.Write(0x20746D66); // = encoding.GetBytes("fmt ") writer.Write(formatChunkSize); writer.Write(formatType); writer.Write(tracks); writer.Write(samplesPerSecond); writer.Write(bytesPerSecond); writer.Write(frameSize); writer.Write(bitsPerSample); writer.Write(0x61746164); // = encoding.GetBytes("data") writer.Write(dataChunkSize); { double theta = frequency * TAU / (double)samplesPerSecond; // 'volume' is UInt16 with range 0 thru Uint16.MaxValue ( = 65 535) // we need 'amp' to have the range of 0 thru Int16.MaxValue ( = 32 767) double amp = volume >> 2; // so we simply set amp = volume / 2 for (int step = 0; step < samples; step++) { short s = (short)(amp * Math.Sin(theta * (double)step)); writer.Write(s); } } mStrm.Seek(0, SeekOrigin.Begin); new System.Media.SoundPlayer(mStrm).Play(); writer.Close(); mStrm.Close(); } // public static void PlayBeep(UInt16 frequency, int msDuration, UInt16 volume = 16383) 

For your question, you do not need most of the code in this method, which creates a byte stream in WAV format, but you can use the trick at the end of the method to avoid having to save bytes in a file.

Answer 4

Try How to play from an array

 PlayerEx pl = new PlayerEx(); private static void PlayArray(PlayerEx pl) { double fs = 8000; // sample freq double freq = 1000; // desired tone short[] mySound = new short[4000]; for (int i = 0; i < 4000; i++) { double t = (double)i / fs; // current time mySound[i] = (short)(Math.Cos(t * freq) * (short.MaxValue)); } IntPtr format = AudioCompressionManager.GetPcmFormat(1, 16, (int)fs); pl.OpenPlayer(format); byte[] mySoundByte = new byte[mySound.Length * 2]; Buffer.BlockCopy(mySound, 0, mySoundByte, 0, mySoundByte.Length); pl.AddData(mySoundByte); pl.StartPlay(); }