Php array_search returns 0 for the first element?

Question

I have this code

$restaurant = array('/restaurant_pos/', '/bar_nightclub_pos/') $current_page = $_SERVER['REQUEST_URI']; if (array_search($current_page, $restaurant)) { echo "KEEP ME"; } 

the problem is that array_search returns 0 because '/ restaurant_pos /' is the first element in the array that causes an if failure ... any ideas on how to check if the value is in the array without failing the first element

Answer 1

 if (array_search($current_page, $restaurant) !== FALSE ) { echo "KEEP ME"; } 

Manual link: http://php.net/manual/en/function.array-search.php

Answer 2

I think it is better to use in_array() in this case

 $restaurant = array('/restaurant_pos/', '/bar_nightclub_pos/') $current_page = $_SERVER['REQUEST_URI']; if (in_array($current_page, $restaurant)) { echo "KEEP ME"; } 

http://php.net/manual/en/function.in-array.php

Answer 3

From my own experience, if you got, for example:

 Array ( [1] => Array ( [0] => a [1] => b ) [2] => Array ( [0] => b ) [4] => Array ( [0] => c ) ) 

In array_search("a", $array[3]) !== FALSE) it returns TRUE the same, therefore, to cover all cases, also in the null element, it is better to use:

 if ( (array_search($element, $array) !== FALSE) && ($array) ) { echo "found"; } 

Hope this helps.