Local ping network in python

Question

Does anyone know how to use python to ping a localhost to find out if it is active or not? We (my team and I) have already tried using

os.system("ping 192.168.1.*") 

But the answer for the unreachable destination is the same as the answer for the host.

Thank you for your help.

Answer 1

Use this ...

 import os hostname = "localhost" #example response = os.system("ping -n 1 " + hostname) #and then check the response... if response == 0: print(hostname, 'is up!') else: print(hostname, 'is down!') 

If you use this script on unix / Linux, replace the -n switch with -c!
Thats all :)

Answer 2

I found that using os.system (...) leads to false positives (as OP said, "destination host is unavailable" == 0).

As stated earlier, using a subprocess works. For simplicity, I recommend doing this and then analyzing the results. You can easily do this, for example:

 if ('unreachable' in output): print("Offline") 

Just check the various outputs you want to check from the ping results. Do 'this' in this question.

Example:

 import subprocess hostname = "10.20.16.30" output = subprocess.Popen(["ping.exe",hostname],stdout = subprocess.PIPE).communicate()[0] print(output) if ('unreachable' in output): print("Offline") 

Answer 3

I encoded a little program a bit. This may not be the exact thing you are looking for, but you can always run a program on the host OS that opens the socket at startup. Here is the ping program itself:

 # Run this on the PC that want to check if other PC is online. from socket import * def pingit(): # defining function for later use s = socket(AF_INET, SOCK_STREAM) # Creates socket host = 'localhost' # Enter the IP of the workstation here port = 80 # Select port which should be pinged try: s.connect((host, port)) # tries to connect to the host except ConnectionRefusedError: # if failed to connect print("Server offline") # it prints that server is offline s.close() #closes socket, so it can be re-used pingit() # restarts whole process while True: #If connected to host print("Connected!") # prints message s.close() # closes socket just in case exit() # exits program pingit() #Starts off whole process 

And here you have a program that can receive a ping request:

 # this runs on remote pc that is going to be checked from socket import * HOST = 'localhost' PORT = 80 BUFSIZ = 1024 ADDR = (HOST, PORT) serversock = socket(AF_INET, SOCK_STREAM) serversock.bind(ADDR) serversock.listen(2) while 1: clientsock, addr = serversock.accept() serversock.close() exit() 

To run the program without showing it, just save the file as .pyw instead of .py. This makes it invisible until the user checks the running processes.

Hope this helped you

Answer 4

Try the following:

 ret = os.system("ping -o -c 3 -W 3000 192.168.1.10") if ret != 0: print "Host is not up" 

-o only one packet is waiting

-W 3000 gives it only 3000 ms to respond to a packet.

-c 3 allows you to try several times so that your ping does not run forever

Answer 5

For simplicity, I use home-made socket-based functions.

 def checkHostPort(HOSTNAME, PORT): """ check if host is reachable """ result = False try: destIp = socket.gethostbyname(HOSTNAME) except: return result s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.settimeout(15) try: conn = s.connect((destIp, PORT)) result = True conn.close() except: pass return result 

if Ip: Port is available, return True

If you want to simulate Ping, you can refer to ping.py

Answer 6

Use this and parse line output

 import subprocess output = subprocess.Popen(["ping.exe","192.168.1.1"],stdout = subprocess.PIPE).communicate()[0]
import subprocess output = subprocess.Popen(["ping.exe","192.168.1.1"],stdout = subprocess.PIPE).communicate()[0]