Xml I / O entry in apache xmlrpc client

Question

I am creating an xmlrpc client with Java using Apache xmlrpc, but could not figure out how to register input / output xml (raw data received and sent). How to do it?

thanks

Answer 1

My workflow was to use custom transport as follows. Perhaps there are more graceful ways to do this.

import java.io.BufferedReader; import java.io.ByteArrayInputStream; import java.io.ByteArrayOutputStream; import java.io.IOException; import java.io.InputStream; import java.io.InputStreamReader; import java.util.logging.Level; import java.util.logging.Logger; import org.apache.xmlrpc.XmlRpcException; import org.apache.xmlrpc.client.XmlRpcClient; import org.apache.xmlrpc.client.XmlRpcStreamTransport; import org.apache.xmlrpc.client.XmlRpcSunHttpTransport; import org.apache.xmlrpc.common.XmlRpcStreamRequestConfig; import org.xml.sax.SAXException; /** * This is a custom XML-RPC transport which logs the outgoing and incoming * XML-RPC messages. */ public class MessageLoggingTransport extends XmlRpcSunHttpTransport { private static final Logger log = Logger.getLogger(MessageLoggingTransport.class.getName()); /** * Default constructor * * @see XmlRpcSunHttpTransport#XmlRpcSunHttpTransport(XmlRpcClient) * @param pClient */ public CookieHandlingTransport(final XmlRpcClient pClient) { super(pClient); } /** * Dumps outgoing XML-RPC requests to the log */ @Override protected void writeRequest(final XmlRpcStreamTransport.ReqWriter pWriter) throws IOException, XmlRpcException, SAXException { final ByteArrayOutputStream baos = new ByteArrayOutputStream(); pWriter.write(baos); log.info(baos.toString()); super.writeRequest(pWriter); } /** * Dumps incoming XML-RPC responses to the log */ @Override protected Object readResponse(XmlRpcStreamRequestConfig pConfig, InputStream pStream) throws XmlRpcException { final StringBuffer sb = new StringBuffer(); try { final BufferedReader reader = new BufferedReader(new InputStreamReader(pStream)); String line = reader.readLine(); while(line != null) { sb.append(line); line = reader.readLine(); } } catch(final IOException e) { log.log(Level.SEVERE, "While reading server response", e); } log.info(sb.toString()); final ByteArrayInputStream bais = new ByteArrayInputStream(sb.toString().getBytes()); return super.readResponse(pConfig, bais); } } 

And then in the code that your XML-RPC client creates:

 final XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl(); config.setServerURL(new URL(url)); final XmlRpcTransportFactory transportFactory = new XmlRpcTransportFactory() { public XmlRpcTransport getTransport() { return new MessageLoggingTransport(client); } }; client = new XmlRpcClient(); client.setTransportFactory(transportFactory); client.setConfig(config); 

Answer 2

Try using the logger for org.apache.xmlrpc.client ; I bet it spills out xml somewhere in this package. Try something like this:

 <appender name="LOG_FILE" class="org.apache.log4j.DailyRollingFileAppender"> <param name="Threshold" value="DEBUG"/> <param name="File" value="C:\xmlrpc_client.log"/> <param name="datePattern" value="'.'yyyy-ww" /> <param name="Append" value="true"/> <layout class="org.apache.log4j.PatternLayout"> <param name="ConversionPattern" value="[%p] %t %d{DATE} %M - %m%n"/> </layout> </appender> <logger name="org.apache.xmlrpc.client"> <level value="DEBUG"/> </logger> <root> <level value="INFO" /> <appender-ref ref="LOG_FILE"/> </root>