Find if a variable is divisible by 2

Question

How to determine if a variable is divisible by 2? In addition, I need a function, if one exists, and execute another function if it is not.

Answer 1

Use module:

// Will evaluate to true if the variable is divisible by 2 variable % 2 === 0 

Answer 2

Seriously, there is no jQuery plugin for odd / even checks?

Well, no more - releasing the “Oven” jQuery plugin under the MIT license to check if this number is odd / even.

Source code is also available at http://jsfiddle.net/7HQNG/

Test kits are available at http://jsfiddle.net/zeuRV/

 (function() { /* * isEven(n) * @args number n * @return boolean returns whether the given number is even */ jQuery.isEven = function(number) { return number % 2 == 0; }; /* isOdd(n) * @args number n * @return boolean returns whether the given number is odd */ jQuery.isOdd = function(number) { return !jQuery.isEven(number); }; })();​ 

Answer 3

You do not need jQuery. Just use the JavaScript modulo operator.

Answer 4

You can use a module operator like this, no jQuery needed. Just replace alerts with your code.

 var x = 2; if (x % 2 == 0) { alert('even'); } else { alert('odd') } 

Answer 5

You can do it better (50% faster than the modulo operator):

odd: x and 1 even :! (x and 1)

Link: high-performance JavaScript, 8. → Bitwise operators

Answer 6

You also can:

 if (x & 1) itsOdd(); else itsEven(); 

Answer 7

 var x = 2; x % 2 ? oddFunction() : evenFunction(); 

Answer 8

 if (x & 1) itIsOddNumber(); else itIsEvenNumber(); 

Answer 9

Please write the following code in the console:

 var isEven = function(deep) { if (deep % 2 === 0) { return true; } else { return false; } }; isEven(44); 

Note: It will return true if the entered number is otherwise incorrect.

Answer 10

Use the module, but .. The answer above is a bit inaccurate. I believe because x is the Number type in JavaScript, which should be a dual purpose instead of a triple destination, for example:

 x % 2 == 0 

Remember to specify your variables as well, so it is obvious that a line cannot be written separately. :-) It is usually used as an if . Hope this helps.

Answer 11

Hope this helps.

 let number = 7; if(number%2 == 0){ //do something; console.log('number is Even'); }else{ //do otherwise; console.log('number is Odd'); } 

Here is the complete function that will record the parity of your input on the console.

 const checkNumber = (x) => { if(number%2 == 0){ //do something; console.log('number is Even'); }else{ //do otherwise; console.log('number is Odd'); } } 

Answer 12

array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

array.each {| x | puts x if x% 2 == 0}

ruby: D

2 4 6 8 10