Fast equivalent [NSBundle bundleForClass: [native class]]

Question

What is the quick equivalent of the following code:

[NSBundle bundleForClass:[self class]] 

I need download resources from a test suite (JSON data)

Answer 1

Never used, but I think it should be like this:

Swift <= 2.x

 NSBundle(forClass: self.dynamicType) 

Swift 3.x

 Bundle(for: type(of: self)) 

Answer 2

Swift 3:

 Bundle(for: type(of: self)) 

Answer 3

I personally like:

 let bun = NSBundle(forClass: self.classForCoder) 

Answer 4

 let bundle = NSBundle(forClass:object_getClass(self)) 

Answer 5

The selected answer did not work for me in a static subclass of UIView, but I found this:

 Bundle(for: self.classForCoder) 

This also works when you want to get a Bundle within a test target.

Answer 6

Download xib for dynamicType class

  let bundle = NSBundle(forClass: self.dynamicType) let nib = UINib(nibName: "CellForAlert", bundle: bundle) let view = nib.instantiateWithOwner(self, options: nil).first as! UIView view.frame = bounds view.autoresizingMask = [.FlexibleWidth, .FlexibleHeight] self.addSubview(view); 

Answer 7

If you work in a classroom, then

 Bundle(for: type(of: self)) 

Sometimes you can work in a structure, then you need to use any class included

 Bundle(for: AnyClassInTheBundle.self) 

Answer 8

In Swift 3.0 you can use:

 func kZWGetBundle() -> Bundle{ return Bundle(for: AnyClass.self as! AnyClass) }