Difference between bitwise inclusion or exclusive or in java

Question

public class Operators { public static void main(String[] args) { int a = 12; System.out.println("Bitwise AND:"+(12&12)); System.out.println("Bitwise inclusive OR:"+(12|12)); System.out.println("Bitwise exclusive OR:"+(12^12)); } } OUTPUT: Bitwise AND:12 Bitwise inclusive OR:12 Bitwise exclusive OR:0 

I understand the first two, but not the third.

Answer 1

XOR indicates whether each bit is different.

1 XOR 1 = 0
1 XOR 0 = 1
0 XOR 1 = 1
0 XOR 0 = 0

In other words, "either not both"

0011 XOR 0101 = 0110

Answer 2

BITWISE INCLUSIVE OR (|) means normal operation or ,

BITWISEE ExCLUSIVE OR (^) means operation xor

Answer 3

Third - XOR operation (Xclusive-OR)

It says: OR should be exclusive: where it will be False (0) in the same way and different from Truth (1).

So 12 in binary will be 1100

So do the bitwise XOR here:

  1 1 0 0 1 1 0 0 --------- 0 0 0 0 --------- 

Each column has the same digit, both are equal to 1 or both are equal to 0 XOR says that both should be different. Hence all zeros

Answer 4

Exclusive or ( XOR ) is defined as:

 0 ^ 0 = 0 1 ^ 0 = 1 0 ^ 1 = 1 1 ^ 1 = 0 

That is, it is 0 when two values ​​are the same, 1 if they are different.

So, given that the two bit patterns are exactly equal, each XORed bit will be evaluated as 0 , since each bit will either have 1 in both positions, or 0 in both positions.

Answer 5

since the operators you use are bitwise operators, so the operands are converted to bits, and then the operator acts on them.

here 12 → 1100 in binary digits (bit)

and the operations of the operators (A), | (OR) and ^ (Exclusive OR or XOR) are as follows:

AB and | ^

0 0 0 0 0

0 1 0 1 1

1 0 0 1 1

1 1 1 1 0

so when you do 12 ^ 12:

A = 1100

B = 1100

Ab ^

1 1 0

1 1 0

0 0 0

0 0 0

and 0000 → 0 in decimal

hence you get 12 ^ 12 = 0 in your third answer