Count consecutive matching words in two oracle lines

Question

I need a query that returns the number of consecutive matches of words in two lines Example:

Table

Id column1 column2 result 1 'foo bar live' 'foo bar' 2 2 'foo live tele' 'foo tele' 1 3 'bar foo live' 'foo bar live' 0 

To get the total I use:

 select id, column1,column2, extractvalue(dbms_xmlgen.getxmltype('select cardinality ( sys.dbms_debug_vc2coll(''' || replace(lower(column1), ' ', ''',''' ) || ''') multiset intersect sys.dbms_debug_vc2coll('''||replace(lower(column2), ' ', ''',''' )||''')) x from dual'), '//text()') cnt from table. 

Can someone suggest a query for similar strings for consecutive matches, just as I want the number of consecutive matches and the number of mappings to be shown together.

Answer 1

Personally, in this situation, I would choose PL / SQL for simple SQL. Something like:

Package Specification:

 create or replace package PKG is function NumOfSeqWords( p_str1 in varchar2, p_str2 in varchar2 ) return number; end; 

Packing case:

 create or replace package body PKG is function NumOfSeqWords( p_str1 in varchar2, p_str2 in varchar2 ) return number is l_str1 varchar2(4000) := p_str1; l_str2 varchar2(4000) := p_str2; l_res number default 0; l_del_pos1 number; l_del_pos2 number; l_word1 varchar2(1000); l_word2 varchar2(1000); begin loop l_del_pos1 := instr(l_str1, ' '); l_del_pos2 := instr(l_str2, ' '); case l_del_pos1 when 0 then l_word1 := l_str1; l_str1 := ''; else l_word1 := substr(l_str1, 1, l_del_pos1 - 1); end case; case l_del_pos2 when 0 then l_word2 := l_str2; l_str2 := ''; else l_word2 := substr(l_str2, 1, l_del_pos2 - 1); end case; exit when (l_word1 <> l_word2) or ((l_word1 is null) or (l_word2 is null)); l_res := l_res + 1; l_str1 := substr(l_str1, l_del_pos1 + 1); l_str2 := substr(l_str2, l_del_pos2 + 1); end loop; return l_res; end; end; 

Test case:

  with t1(Id1, col1, col2) as( select 1, 'foo bar live' ,'foo bar' from dual union all select 2, 'foo live tele' ,'foo tele' from dual union all select 3, 'bar foo live' ,'foo bar live'from dual ) select id1 , col1 , col2 , pkg.NumOfSeqWords(col1, col2) as res from t1 ; 

Result:

  ID1 COL1 COL2 RES ---------- ------------- ------------ ---------- 1 foo bar live foo bar 2 2 foo live tele foo tele 1 3 bar foo live foo bar live 0 

Answer 2

Why refuse the approach to the request. I know this is a little complicated, and I hope someone can work on it to improve it, but working on it in my free time, I was able to survive a day of calls ...

Here is SQLFidlle

 SELECT Table1.id, Table1.column1, Table1.column2, max(nvl(tl,0)) RESULT FROM ( SELECT id, column1, column2, LEVEL l, decode(LEVEL, 1, substr(column1, 1, instr(column1,' ', 1, LEVEL) -1), substr(column1, 1, (instr(column1,' ', 1, LEVEL ))) ) sub1, decode(LEVEL, 1, substr(column2, 1, instr(column2,' ', 1, LEVEL) -1), substr(column2, 1, (instr(column2,' ', 1, LEVEL ))) ) sub2 FROM (SELECT id, column1 || ' ' column1, column2 || ' ' column2 FROM Table1) WHERE decode(LEVEL, 1, substr(column1, 1, instr(column1,' ', 1, LEVEL) -1), substr(column1, 1, (instr(column1,' ', 1, LEVEL ))) ) = decode(LEVEL, 1, substr(column2, 1, instr(column2,' ', 1, LEVEL) -1), substr(column2, 1, (instr(column2,' ', 1, LEVEL ))) ) START WITH column1 IS NOT NULL CONNECT BY instr(column1,' ', 1, LEVEL) > 0 ) t RIGHT OUTER JOIN Table1 ON trim(t.column1) = Table1.column1 AND trim(t.column2) = Table1.column2 AND t.id = Table1.id GROUP BY Table1.id, Table1.column1, Table1.column2 ORDER BY max(nvl(tl,0)) DESC