Exit (1) in the file leads to script status 0

Question

On an Ubuntu machine:

$ php -v PHP 5.5.10-1~dotdeb.1 (cli) (built: Mar 6 2014 18:55:59) Copyright (c) 1997-2014 The PHP Group Zend Engine v2.5.0, Copyright (c) 1998-2014 Zend Technologies with uopz v2.0.4, Copyright (c) 2014, by Joe Watkins <[e-mail]> with Zend OPcache v7.0.3, Copyright (c) 1999-2014, by Zend Technologies with Xdebug v2.2.3, Copyright (c) 2002-2013, by Derick Rethans 

My test.php file is simple:

 <?php exit(1); 

I would expect this php test.php || echo "error" command php test.php || echo "error" php test.php || echo "error" will show "error", but it will exit with status 0.

 $ php test.php $ echo $? 0 

But on the same machine, the same code, but not in the file, works as expected:

 $ php -r "exit(1);" || echo "error" error 

or

 $ php -r "exit(1);" $ echo $? 1 

On another machine (archlinux) with php:

 PHP 5.5.13 (cli) (built: May 29 2014 05:46:58) Copyright (c) 1997-2014 The PHP Group Zend Engine v2.5.0, Copyright (c) 1998-2014 Zend Technologies 

All cases work as expected, even when the code is run from a file, the status code is 1.

This is a real problem because git is dependent on these status codes, and Jenkins and I cannot do this.

Could this be configuration related? I checked cli php.ini and did not find anything suspicious.

Answer 1

This is an extension of uopz . It "corrupts" the exit code. An error has been opened about this problem.

You can try setting the configuration uopz.overloads=0 , as recommended in the error comments. This, unfortunately, did not work for me. Fixed the problem with disabling the extension.