You should not get the latest error if you use this exact code:
res.status(200).send('Success 1')
I assume that you are not using the string "Success 1", but instead a digital variable or value:
let value = 123; res.status(200).send(value);
This will cause a warning. Instead, make sure value compressed:
let value = 123; res.status(200).send(String(value));
robertklep
source share