I have a script that I would like to continue to use, but it looks like I need to find some workaround for the error in Python 3 or return to version 2.6, and therefore you will have to downgrade other scripts as well ...
Hopefully someone here has already managed to find a workaround.
The problem is that due to new changes in Python 3.0 regarding bytes and strings, not all library files are apparently tested.
I have a script that loads a page from a web server. This script passed the username and password as part of the url in python 2.6, but in Python 3.0 this no longer works.
For example, this:
import urllib.request; url = "http://username:password@server/file"; urllib.request.urlretrieve(url, "temp.dat");
fails with this exception:
Traceback (most recent call last): File "C:\Temp\test.py", line 5, in <module> urllib.request.urlretrieve(url, "test.html"); File "C:\Python30\lib\urllib\request.py", line 134, in urlretrieve return _urlopener.retrieve(url, filename, reporthook, data) File "C:\Python30\lib\urllib\request.py", line 1476, in retrieve fp = self.open(url, data) File "C:\Python30\lib\urllib\request.py", line 1444, in open return getattr(self, name)(url) File "C:\Python30\lib\urllib\request.py", line 1618, in open_http return self._open_generic_http(http.client.HTTPConnection, url, data) File "C:\Python30\lib\urllib\request.py", line 1576, in _open_generic_http auth = base64.b64encode(user_passwd).strip() File "C:\Python30\lib\base64.py", line 56, in b64encode raise TypeError("expected bytes, not %s" % s.__class__.__name__) TypeError: expected bytes, not str
Apparently base64-encoding now needs bytes and prints a string, and thus urlretrieve (or some code in it) that builds a username string: password and tries to make base64-encode for easy authorization fails .
If I try to use urlopen instead, like this:
import urllib.request; url = "http://username:password@server/file"; f = urllib.request.urlopen(url); contents = f.read();
Then this failure is eliminated:
Traceback (most recent call last): File "C:\Temp\test.py", line 5, in <module> f = urllib.request.urlopen(url); File "C:\Python30\lib\urllib\request.py", line 122, in urlopen return _opener.open(url, data, timeout) File "C:\Python30\lib\urllib\request.py", line 359, in open response = self._open(req, data) File "C:\Python30\lib\urllib\request.py", line 377, in _open '_open', req) File "C:\Python30\lib\urllib\request.py", line 337, in _call_chain result = func(*args) File "C:\Python30\lib\urllib\request.py", line 1082, in http_open return self.do_open(http.client.HTTPConnection, req) File "C:\Python30\lib\urllib\request.py", line 1051, in do_open h = http_class(host, timeout=req.timeout)
Apparently, parsing the URLs in this "next url search library" doesn't know what to do with the username and passwords in the url.
What other options do I have?