Convert an xml element whose contents are inside CDATA

Question

I have an xml snippet as below

<Detail uid="6"> <![CDATA[ <div class="heading">welcome to my page</div> <div class="paragraph">this is paraph</div> ]]> </Detail>

and i want to change

 <div class="heading">...</div> to <h1>Welcome to my page</h1> <div class="paragraph">...</div> to <p>this is paragraph</p> 

You know how I can do this in xslt 1.0

Answer 1

How to start two conversions.

Pass 1.)

 <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes" encoding="UTF-8"/> <xsl:template match="/"> <xsl:apply-templates /> </xsl:template> <xsl:template match="Detail"> <Detail> <xsl:copy-of select="@*"/> <xsl:value-of select="." disable-output-escaping="yes" /> </Detail> </xsl:template> </xsl:stylesheet> 

Will produce:

 <?xml version="1.0" encoding="UTF-8"?> <Detail uid="6"> <div class="heading">welcome to my page</div> <div class="paragraph">this is paraph</div> </Detail> 

Pass 2.)

 <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes" encoding="UTF-8"/> <xsl:template match="/"> <xsl:apply-templates /> </xsl:template> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*| node()" /> </xsl:copy> </xsl:template> <xsl:template match="div[@class='heading']"> <h1><xsl:value-of select="."/></h1> </xsl:template> <xsl:template match="div[@class='paragraph']"> <p><xsl:value-of select="."/></p> </xsl:template> </xsl:stylesheet> 

It produces:

 <?xml version="1.0" encoding="UTF-8"?> <Detail uid="6"> <h1>welcome to my page</h1> <p>this is paraph</p> </Detail> 

Answer 2

You cannot tell XSL 1.0 to pull a string from CDATA and parse it as XML.

Answer 3

You cannot “delete” CDATA, but you can achieve the desired result somewhat crudely:

 <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <Detail> <xsl:variable name="before" select="substring-before(//Detail,'&lt;div class=&quot;heading&quot;&gt;')" /> <xsl:variable name="afteropen" select="substring-after(//Detail,'&lt;div class=&quot;heading&quot;&gt;')" /> <xsl:variable name="body" select="substring-before($afteropen, '&lt;/div&gt;')" /> <xsl:variable name="after" select="substring-after($afteropen, '&lt;/div&gt;')" /> <xsl:value-of select="concat($before, '&lt;h1&gt;', $body, '&lt;/h1&gt;',$after)" disable-output-escaping="yes" /> </Detail> </xsl:template> </xsl:stylesheet> 

This will work for the first type of div you are trying to parse, and you can follow something similar with the second. This can be made more general with some efforts.