How to use logical OR in SPARQL regex ()?

Question

I use this line in a SPARQL query in my python program:

FILTER regex(?name, "%s", "i" ) 

(where %s is the search text entered by the user)

I want this to match if either ?name or ?featurename contains %s , but I cannot find any documentation or tutorial on using regex (). I tried a couple of things that seemed reasonable:

 FILTER regex((?name | ?featurename), "%s", "i" ) FILTER regex((?name || ?featurename), "%s", "i" ) FILTER regex((?name OR ?featurename), "%s", "i" ) FILTER regex((?name, ?featurename), "%s", "i" ) 

and each of them without ()

 FILTER regex(?name, "%s", "i" ) || regex(?featurename, "%s", "i" ) 

What is the right way to do this? Thanks

UPDATE: Using UNION. But I realized that it also works if you just repeat the regex part () like this:

 FILTER (regex(?name, "%s", "i") || regex(?featurename, "%s", "i" )) 

Both solutions seem a bit confusing in that you need to use a two-element tuple with copies of the same string to fill as %s s.

Answer 1

How about this?

 SELECT ?thing WHERE { { ?thing x:name ?name . FILTER regex(?name, "%s", "i" ) } UNION { ?thing x:featurename ?name . FILTER regex(?featurename, "%s", "i" ) } }