How to compare shell script?

Question

Or, why does the following script not print anything?

x=1 if[ $x = 1 ] then echo "ok" else echo "no" fi

+7

Tom brito Mar 17 '11 at 18:19

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3 answers

Short solution with AND and OR labels:

 x=1 (( $x == 1 )) && echo "ok" || echo "no"

+4

user unknown Mar 17 '11 at 18:35

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It depends on the language. With bash, you can use the == operator. Otherwise, you can use -eq -lt -gt for equal, lower, more than.

 $ x=1 $ if [ "$x" == "2" ]; then echo "yes"; else echo "no"; fi no

Edit: Added spaces arround == and tested with 2.

+1

Aif Mar 17 '11 at 18:23

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William durand · Accepted Answer · 2011-03-17T18:22:55+0000

With numbers, use -eq , -ne , ... for equals, not equals, ...

 x=1 if [ $x -eq 1 ] then echo "ok" else echo "no" fi

And for others, use == not = .