Python template

Question

How to write a render_user function that takes one of the tuples returned by a list of users and a row pattern and returns the data substituted into the pattern, for example:

>>> tpl = "<a href='mailto:%s'>%s</a>" >>> render_user((' [e-mail] ', 'matt rez', ), tpl) "<a href='mailto: [e-mail] >Matt rez</a>" 

Any help would be appreciated

Answer 1

There is no need to create a function if you do not require it:

 >>> tpl = "<a href='mailto:%s'>%s</a>" >>> s = tpl % (' [e-mail] ', 'matt rez', ) >>> print s "<a href='mailto: [e-mail] '>matt rez</a>" 

If you use 2.6+, you can use the new format function along with the mini-language:

 >>> tpl = "<a href='mailto:{0}'>{1}</a>" >>> s = tpl.format(' [e-mail] ', 'matt rez') >>> print s "<a href='mailto: [e-mail] '>matt rez</a>" 

Wrapped in function:

 def render_user(userinfo, template="<a href='mailto:{0}'>{1}</a>"): """ Renders a HTML link for a given ``userinfo`` tuple; tuple contains (email, name) """ return template.format(userinfo) # Usage: userinfo = (' [e-mail] ', 'matt rez') print render_user(userinfo) # same output as above 

Additional loan:

Instead of using the regular tuple object, try using the more robust and friendly namedtuple provided by the collections module. It has the same performance (and memory consumption) as a regular tuple . A short entry into the named tuples can be found in this PyCon 2011 video (fast forward to ~ 12 m): http://blip.tv/file/4883247

Answer 2

  from string import Template
 t = Template ("$ {my} + $ {your} = 10")
 print (t.substitute ({"my": 4, "your": 6}))