Geek Answers Handbook

Sending coding response in json

I use a lot of jQuery in the project I'm working on.

I have a javascript function that makes an ajax request to a controller that returns data in JSON.

I would like to show a user-friendly message informing the user that he / she does not yet have the stored information. But I am confused as to how to send the response in JSON so that my javascript function can determine if the user will have information displayed.

Here is my javascript function:

function latest_pheeds() { var action = url+"pheeds/latest_pheeds"; $('#pheed-stream').html('<div class="loading"></div>'); $('.loading').append('<img src="'+pheed_loader_src+'" />'); $.ajax({ url:action, type:'GET', dataType:'json', error: function () { }, success:function(data) { $('.loading').fadeOut('slow'); $.each(data,function(index,item) { $('#pheed-stream').append ( '<div class="pheed" id="'+item.pheed_id+'">'+ '<p><a class="user_trigger" href="users/info/'+item.user_id+'">' +item.user_id+'</a></p>'+ '<p>'+item.pheed+'</p>'+ '<div class="pheed_meta">'+ '<span>'+item.datetime+' Ago</span>'+ '<span class="cm">'+item.comments+ '<img class="comment_trigger" src="/pheedbak/assets/img/comment.png" title="Click to comment on pheed" onclick="retrieve_comments('+item.pheed_id+')">'+ '</span>'+ '<span>'+item.repheeds+ ' Repheeds'+ '<img class="repheed_trigger" src="/pheedbak/assets/img/communication.png" title="Click to repheed" onclick="repheed('+item.pheed_id+')">'+ '</span>'+ '<span>'+ 'Favourite'+ '<img class="favourite_trigger" src="/pheedbak/assets/img/star.png" title="Click to make this a favourite" onclick="favourite_pheed('+item.pheed_id+')" />'+ '</span>'+ '</div>'+ '</div>' ); }); } }); }

And so, that controller function executes an ajax request for

 function latest_pheeds() { //Confirm if a user is logged before allowing access if($this->isLogged() == true) { //load the pheed model for database interaction $this->load->model('pheed_model'); //load user model $this->load->model('user_model'); //load comment model $this->load->model('comment_model'); //store the pheeds to a the $data variable $data = $this->pheed_model->get_latest_pheeds(); //Load the date helper to calculate time difference between post time and current time $this->load->helper('date'); //Current time(unix timetamp) $time = time(); //pheeds $pheeds = array(); if(count($data) > 0 ) { foreach($data as $pheed) { $row['pheed_id'] = $pheed->pheed_id; $row['user_id'] = $this->user_model->return_username($pheed->user_id); $row['pheed'] = $pheed->pheed; $row['datetime'] = timespan($pheed->datetime,$time); $row['comments'] = $this->comment_model->count_comments($pheed->pheed_id); $row['repheeds'] = $pheed->repheeds; $pheeds[] = $row; } echo json_encode($pheeds); $response['response'] = "Ok"; $res[] = $response; echo json_encode($res)."\n"; } } else { }

It generates JSON output, but the syntax is broken, so I can not read it using javascript, but as soon as I get rid of the following code from the above method, it works fine

  $response['response'] = "Ok"; $res[] = $response; echo json_encode($res)."\n";
+7
source share
1 answer

You should only use json_encode ($ data) once in the response, if you want to output more material, you need to combine your data into one array and send it.

EDIT: To be clear, one way to do this is:

 echo json_encode(array('pheeds' => $pheeds, 'res' => $res));

Then in JS you get an array with the keys "pheeds" and "res".

Although this may be of little practical value, I would also recommend doing this before you echo the json encoding:

 header('Content-Type: application/json');
+14
source

More articles:


All Articles