Resolving file upload error 4

Question

I am trying to upload multiple files to my server. If I try to upload a single file, it works fine. but if I try more than one, it will give me error code 4, although it will correctly print the name of all files. Nothing uploaded. I have the correct input type. Can anybody help me?

Choose Image:&nbsp;&nbsp;<input name="uploadedfile[]" type="file" multiple="true"/><br /><br /><br /> <input type="submit" value="Upload Image!" style="margin-left:100px;"/> 

Below is the code:

 $i=0; foreach($_FILES['uploadedfile']['name'] as $f) { $file['name'] = $_FILES['uploadedfile']['name'][$i]; $file['type'] = $_FILES['uploadedfile']['type'][$i]; $file['tmp_name'] = $_FILES['uploadedfile']['tmp_name'][$i]; $file['error'] = $_FILES['uploadedfile']['error'][$i]; $file['size'] = $_FILES['uploadedfile']['size'][$i]; if ($file["error"] > 0) { echo "Error Code: " . $file["error"]; } $target_path = "uploads/".basename($file["name"]); if(move_uploaded_file($file["tmp_name"], $target_path)) { echo basename($file['name'])."<br />"; echo basename($file['tmp_name'])."<br />"; echo $target_path; } else{ echo "There was an error uploading the file, please try again!"; } $i++; } 

and my HTML form

 <div id="album_slider"> <div style="text-align:center;margin:20px auto;font-size:27px;">Upload Image</div> <br style="clear:both;font-size:0;line-height:0;height:0;"/> <div style="width:700px;margin:auto;height:250px;text-align:left;"> <form enctype="multipart/form-data" action="uploader.php" method="POST" name="form"> Image Name:&nbsp;&nbsp;&nbsp;&nbsp;<input type="text" name="image_name" id="image_name"/><br /><br /><br /> <input type="hidden" name="a_id" id="a_id" value="<?php echo $a_id; ?>"/> Choose Image:&nbsp;&nbsp;<input name="uploadedfile[]" type="file" multiple="true"/><br /><br /><br /> <input type="submit" value="Upload Image!" style="margin-left:100px;"/> </form> </div> <br style="clear:both;font-size:0;line-height:0;height:1px;"/> </div> 

Answer 1

Try:

  foreach ($ _FILES ["uploadedfile"] ["error"] as $ key => $ error) {
    if ($ error == UPLOAD_ERR_OK) {
        echo "$ error_codes [$ error]";
        move_uploaded_file (
          $ _FILES ["uploadedfile"] ["tmp_name"] [$ key],
          $ target_path
        ) or die ("Problems with upload");
    }
 }

Answer 2

Well, this will happen if you want to download MULTIPLE files, but your code is only for processing one separate file.

Go ahead and read how to handle multiple files here:
http://php.net/manual/en/features.file-upload.multiple.php

Answer 3

Use status check as below code

 if(isset($_FILES["qImage"]) && !empty($_FILES["qImage"]["name"])){ $imgSubQuestion = $_FILES["qImage"]; } if(isset($_FILES["sImage"]) && !empty($_FILES["sImage"]["name"])){ $imgSolution = $_FILES["sImage"]; }