Javascript regular expressions as functions?

Question

Obviously, in Firefox 3.6 it was legal:

/[0-9]{3}/('23 2 34 678 9 09')

and the result was "678".

FF8 does not have. What is the correct syntax now?

+7

bmargulies Dec 17 '11 at 20:01

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3 answers

I don't know why you need this syntax, but here is something for lulz:

 RegExp = (function(){ var old = RegExp; return function(){ return old.prototype.exec.bind( old.apply( this, arguments ) ); }; })()

Then:

 new RegExp( "[0-9]{3}" )('23 2 34 678 9 09') //["678"]

Please note that when using literals, the hack constructor will not be called, so it only works when using new RegExp ; P

+3

Esailija Dec 17 '11 at 20:15

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+2

HBP Dec 17 '11 at 20:28

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Adam rackis · Accepted Answer · 2011-12-17T20:02:50+0000

Do you want to

 /[0-9]{3}/.test('23 2 34 678 9 09');

or

 /[0-9]{3}/.exec('23 2 34 678 9 09');