How to set timeout on python socket recv method?

Question

I need to set a timeout on the python socket recv method. How to do it?

Answer 1

A typical approach is to use select () until the data is available or until a timeout occurs. Call recv() only when data is actually available. To be safe, we also set the socket to non-blocking mode to ensure that recv() will never block indefinitely. select() can also be used to wait for more than one socket at a time.

 import select mysocket.setblocking(0) ready = select.select([mysocket], [], [], timeout_in_seconds) if ready[0]: data = mysocket.recv(4096) 

If you have many open file descriptors, poll () is a more efficient alternative to select() .

Another option is to set a timeout for all operations on the socket using socket.settimeout() , but I see that you explicitly rejected this solution in a different answer.

Answer 2

there socket.settimeout()

Answer 3

As already mentioned, select.select() and socket.settimeout() will work.

Note that you may need to call settimeout twice for your needs, for example.

 sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) # accept can throw socket.timeout sock.settimeout(5.0) conn, addr = sock.accept() # recv can throw socket.timeout conn.settimeout(5.0) conn.recv(1024) 

Answer 4

You can set the wait time before receiving a response and after receiving a response set it to No:

 sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) sock.settimeout(5.0) data = sock.recv(1024) sock.settimeout(None) 

Answer 5

The timeout you are looking for is the connection socket timeout, not the main socket if you are implementing the server side. In other words, there is another timeout for the connection socket object, which is the result of socket.accept() . Hence:

 sock.listen(1) connection, client_address = sock.accept() connection.settimeout(5) # This is the one that affects recv() method. connection.gettimeout() # This should result 5 sock.gettimeout() # This outputs None when not set previously, if I remember correctly. 

If you implement the client side, it will be simple.

 sock.connect(server_address) sock.settimeout(3) 

Answer 6

As mentioned in previous answers, you can use something like: .settimeout() For example:

 import socket s = socket.socket() s.settimeout(1) # Sets the socket to timeout after 1 second of no activity host, port = "somehost", 4444 s.connect((host, port)) s.send("Hello World!\r\n") try: rec = s.recv(100) # try to receive 100 bytes except socket.timeout: # fail after 1 second of no activity print("Didn't receive data! [Timeout]") finally: s.close() 

Hope this helps !!

Answer 7

You can use socket.settimeout() which takes an integer argument representing the number of seconds. For example, socket.settimeout(1) set the timeout to 1 second

Answer 8

try this, it uses basic C.

 timeval = struct.pack('ll', 2, 100) s.setsockopt(socket.SOL_SOCKET,SO_RCVTIMEO, timeval)