C # Openfiledialog

Question

When I open a file using this code

if (ofd.ShowDialog() == DialogResult.OK) text = File.ReadAllText(ofd.FileName, Encoding.Default); 

A window will appear and ask me to select a file (the file name is empty, as you can see in the image)

If I press the "Open" button a second time to open the file, the file name will display the path to the previous selected file (see image). How can I clear this path every time he clicks the open button?

Answer 1

You are probably using the same instance of OpenFileDialog each time you click the button, which means that the previous file name is still stored in the FileName property. Before displaying the dialog again, you must clear the FileName property:

 ofd.FileName = String.Empty; if (ofd.ShowDialog() == DialogResult.OK) text = File.ReadAllText(ofd.FileName, Encoding.Default); 

Answer 2

try the following:

 ofd.FileName = String.Empty; 

Answer 3

You need to reset the file name.

  openFileDialog1.FileName= ""; 

or

  openFileDialog1.FileName= String.Empty() 

Answer 4

you can simply add this line before calling ShowDialog() :

 ofd.FileName = String.Empty; 

Answer 5

To clear only the file name (and not the selected path), you can set the FileName property to string.Empty .

Answer 6

 private void button1_Click(object sender, EventArgs e) { openFileDialog1.ShowDialog(); } private void openFileDialog1_FileOk(object sender, CancelEventArgs e) { label1.Text = sender.ToString(); } 

How about this one.