C ++ class is not a base for itself

Question

I'm not quite sure how much information is needed to answer this question, so tell me if additional information is needed.

Im modifying the big code that I wrote when I suddenly came across this message: error: type 'integer' is not a direct base of 'integer' . I know its inheritance problem, but im doesn't inherit other classes.

The code causing this problem is

 integer(const std::string & val, uint16_t base): integer(val.begin(), val.end(), base) {} 

and

 integer(iterator start, iterator end, uint16_t base) 

.

What do I need to do to fix this?

EDIT: im compiling with -std = C ++ 0x, which according to the answers should be able to compile if my compiler is not deprecated: gcc 4.6.2 I think

Answer 1

It looks like you are trying to directly call another constructor. You cannot do this in C ++ 03, but you can do just that in C ++ 11 :

 class SomeType { int number; public: SomeType(int new_number) : number(new_number) {} SomeType() : SomeType(42) {} }; 

For this you need g ++ 4.7 or later, 4.6 does not support this function yet, even with -std = C ++ 0x, which I tested in both versions on my system.

Answer 2

It is not possible to call other constructors of the same class like this (in C ++ 11 there are delegating constructors). You need to initialize the members of the class (as you probably did in another constructor).

EDIT:

According to C ++ 0x / C ++ 11 Support in GCC , delegating constructors were implemented in GCC v4.7

Answer 3

You cannot call the constructor of the same class in the list of initializers of another constructor (in C ++ 03). But you can initialize members accordingly:

 integer(const std::string & val, uint16_t base): _start(val.begin()) _end(val.end()) _base(base) {} 

Answer 4

It is not supported in g ++ - 4.6 ("Delegation of Constructors | N1986 | No"), but it is supported in 4.7 .