CUDA C programming for 2 video cards

I am very new to CUDA programming and read the "CUDA C Programming Guide" provided by nvidia. ( http://developer.download.nvidia.com/compute/DevZone/docs/html/C/doc/CUDA_C_Programming_Guide.pdf )

On page 25, it has the following C code, which performs matrix multiplication. Could you tell me how can I make this code on two devices? (if I have two nvida CUDA support cards installed on my computer). Could you show me an example.

// Matrices are stored in row-major order: // M(row, col) = *(M.elements + row * M.stride + col) typedef struct { int width; int height; int stride; float* elements; } Matrix; // Get a matrix element __device__ float GetElement(const Matrix A, int row, int col) { return A.elements[row * A.stride + col]; } // Set a matrix element __device__ void SetElement(Matrix A, int row, int col, float value) { A.elements[row * A.stride + col] = value; } // Get the BLOCK_SIZExBLOCK_SIZE sub-matrix Asub of A that is // located col sub-matrices to the right and row sub-matrices down // from the upper-left corner of A __device__ Matrix GetSubMatrix(Matrix A, int row, int col) { Matrix Asub; Asub.width = BLOCK_SIZE; Asub.height = BLOCK_SIZE; Asub.stride = A.stride; Asub.elements = &A.elements[A.stride * BLOCK_SIZE * row + BLOCK_SIZE * col]; return Asub; } // Thread block size #define BLOCK_SIZE 16 // Forward declaration of the matrix multiplication kernel __global__ void MatMulKernel(const Matrix, const Matrix, Matrix); // Matrix multiplication - Host code // Matrix dimensions are assumed to be multiples of BLOCK_SIZE void MatMul(const Matrix A, const Matrix B, Matrix C) { // Load A and B to device memory Matrix d_A; d_A.width = d_A.stride = A.width; d_A.height = A.height; size_t size = A.width * A.height * sizeof(float); cudaMalloc(&d_A.elements, size); cudaMemcpy(d_A.elements, A.elements, size, cudaMemcpyHostToDevice); Matrix d_B; d_B.width = d_B.stride = B.width; d_B.height = B.height; size = B.width * B.height * sizeof(float); cudaMalloc(&d_B.elements, size); cudaMemcpy(d_B.elements, B.elements, size, cudaMemcpyHostToDevice); // Allocate C in device memory Matrix d_C; d_C.width = d_C.stride = C.width; d_C.height = C.height; size = C.width * C.height * sizeof(float); cudaMalloc(&d_C.elements, size); // Invoke kernel dim3 dimBlock(BLOCK_SIZE, BLOCK_SIZE); dim3 dimGrid(B.width / dimBlock.x, A.height / dimBlock.y); MatMulKernel<<<dimGrid, dimBlock>>>(d_A, d_B, d_C); // Read C from device memory cudaMemcpy(C.elements, d_C.elements, size, cudaMemcpyDeviceToHost); // Free device memory cudaFree(d_A.elements); cudaFree(d_B.elements); cudaFree(d_C.elements); } // Matrix multiplication kernel called by MatMul() __global__ void MatMulKernel(Matrix A, Matrix B, Matrix C) { // Block row and column int blockRow = blockIdx.y; int blockCol = blockIdx.x; // Each thread block computes one sub-matrix Csub of C Matrix Csub = GetSubMatrix(C, blockRow, blockCol); // Each thread computes one element of Csub // by accumulating results into Cvalue float Cvalue = 0; // Thread row and column within Csub int row = threadIdx.y; int col = threadIdx.x; // Loop over all the sub-matrices of A and B that are // required to compute Csub // Multiply each pair of sub-matrices together // and accumulate the results for (int m = 0; m < (A.width / BLOCK_SIZE); ++m) { // Get sub-matrix Asub of A Matrix Asub = GetSubMatrix(A, blockRow, m); // Get sub-matrix Bsub of B Matrix Bsub = GetSubMatrix(B, m, blockCol); // Shared memory used to store Asub and Bsub respectively __shared__ float As[BLOCK_SIZE][BLOCK_SIZE]; __shared__ float Bs[BLOCK_SIZE][BLOCK_SIZE]; // Load Asub and Bsub from device memory to shared memory // Each thread loads one element of each sub-matrix As[row][col] = GetElement(Asub, row, col); Bs[row][col] = GetElement(Bsub, row, col); // Synchronize to make sure the sub-matrices are loaded // before starting the computation __syncthreads(); // Multiply Asub and Bsub together for (int e = 0; e < BLOCK_SIZE; ++e) Cvalue += As[row][e] * Bs[e][col]; // Synchronize to make sure that the preceding // computation is done before loading two new // sub-matrices of A and B in the next iteration __syncthreads(); } // Write Csub to device memory // Each thread writes one element SetElement(Csub, row, col, Cvalue); } 
+7
source share
2 answers

There is no β€œautomatic” way to run the CUDA kernel on multiple GPUs.

You will need to develop a way to decompose the matrix multiplication problem into independent operations that can be performed in parallel (so that one on each GPU is parallel). As a simple example:

C = AB equivalent to C = [A].[B1|B2] = [A.B1|A.B2] , where B1 and B2 are matrices of suitable size containing columns of the matrices B and | denote columnar concatenation. You can calculate A.B1 and A.B2 as separate matrix multiplication operations, and then perform concatenation when copying the resulting submatrices back to the host memory.

Once you have a suitable decomposition scheme, you then implement it using the standard multi-gpu tools in the CUDA 4.x API. For a great overview of multi-GPU programs using the CUDA API, I recommend watching the excellent Paulius Micikevicius conversations from GTC 2012, which are available as video streaming and PDF here .

+6
source

The basics are described in the CUDA C Programming Guide in Section 3.2.6.

Basically, you can set which GPU the current host thread is running on by calling cudaSetDevice() . However, you need to write your own code to decompose your routines, which need to be divided into several GPUs.

+2
source

All Articles