Random Strings in Python

Question

How to create a random string in Python?

I need it to be a number, and then repeating the character until you finish, this is what I created.

def random_id(length): number = '0123456789' alpha = 'abcdefghijklmnopqrstuvwxyz' id = '' for i in range(0,length,2): id += random.choice(number) id += random.choice(alpha) return id 

Answer 1

Generating strings from (for example) lowercase characters:

 import random, string def randomword(length): letters = string.ascii_lowercase return ''.join(random.choice(letters) for i in range(length)) 

Results:

 >>> randomword(10) 'vxnxikmhdc' >>> randomword(10) 'ytqhdohksy' 

Answer 2

Since this question is fair, uh, random, this might work for you:

 >>> import uuid >>> print uuid.uuid4() 58fe9784-f60a-42bc-aa94-eb8f1a7e5c17 

Answer 3

 >>> import random >>> import string >>> s=string.lowercase+string.digits >>> ''.join(random.sample(s,10)) 'jw72qidagk 

Answer 4

Answer to the original question:

 os.urandom(n) 

Quote: http://docs.python.org/2/library/os.html

Returns a string of n random bytes suitable for use in cryptography.

This function returns random bytes from random random source. The returned data should be unpredictable for cryptographic applications, although its exact quality depends on the OS implementation. On a UNIX-like system, this will request / dev / urandom, and on Windows it will use CryptGenRandom. If the source of randomness is not found, NotImplementedError will be raised.

For a convenient interface with a random number generator on your platform, see random.SystemRandom.

Answer 5

You can create random ascii characters, for example:

 import random print chr(random.randint(0,255)) 

And then create a longer line, for example:

 len = 50 print ''.join( [chr(random.randint(0,255)) for i in xrange(0,len)] ) 

Answer 6

You didn’t talk very much about what random string you need. But in any case, you should study the random module.

Below is a very simple solution.

 import random def randstring(length=10): valid_letters='ABCDEFGHIJKLMNOPQRSTUVWXYZ' return ''.join((random.choice(valid_letters) for i in xrange(length))) print randstring() print randstring(20) 

Answer 7

 random_name = lambda length: ''.join(random.sample(string.letters, length)) 

Length

should be <= len (string.letters) = 53. example result

  >>> [random_name(x) for x in range(1,20)] ['V', 'Rq', 'YtL', 'AmUF', 'loFdS', 'eNpRFy', 'iWFGtDz', 'ZTNgCvLA', 'fjUDXJvMP', 'EBrPcYKUvZ', 'GmxPKCnbfih', 'nSiNmCRktdWZ', 'VWKSsGwlBeXUr', 'i stIFGTUlZqnav', 'bqfwgBhyTJMUEzF', 'VLXlPiQnhptZyoHq', 'BXWATvwLCUcVesFfk', 'jLngHmTBtoOSsQlezV', 'JOUhklIwDBMFzrTCPub'] >>> 

Enjoy .;)

Answer 8

Sometimes I wanted random strings to be illegible, half-forgotten.

 import random def randomWord(length=5): consonants="bcdfghjklmnpqrstvwxyz" vowels="aeiou" return "".join(random.choice((consonants,vowels)[i%2]) for i in range(length)) 

Then,

 >>> randomWord() nibit >>> randomWord() piber >>> randomWord(10) rubirikiro 

To avoid four-letter words, do not set length 4.

Jim

Answer 9

Install this package:

 pip3 install py_essentials 

And use this code:

 from py_essentials import simpleRandom as sr print(sr.randomString(4)) 

More information about the method and other parameters is available here.

Answer 10

This function generates a random string consisting of uppercase and lowercase letters, numbers, length delimiter, no_of_blocks to indicate the format of the string

For example: len_sep = 4, no_of_blocks = 4 will generate the following pattern,

F4nQ-Vh5z-JKEC-WhuS

Where, the length delimiter will add a "-" after 4 characters

XXXX-

none of the blocks will generate the next character set as a string

XXXX - XXXX - XXXX - XXXX

if you need one random string, just leave the no_of_blocks variable equal to 1 and len_sep to indicate the length of the random string.

For example: len_sep = 10, no_of_blocks = 1, will generate the following pattern, i.e. random string 10 in length

F01xgCdoDU

 import random as r def generate_random_string(len_sep, no_of_blocks): random_string = '' random_str_seq = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ" for i in range(0,len_sep*no_of_blocks): if i % len_sep == 0 and i != 0: random_string += '-' random_string += str(random_str_seq[r.randint(0, len(random_str_seq) - 1)]) return random_string 

Answer 11

 import random import string def get_random_string(size): chars = string.ascii_lowercase+string.ascii_uppercase+string.digits ''.join(random.choice(chars) for _ in range(size)) print(get_random_string(20) 

output: FfxjmkyyLG5HvLeRudDS