How to use the OR clause in a JavaScript IF statement?

Question

I understand that in JavaScript you can write:

if (A && B) { do something } 

But how can I implement OR, for example:

 if (A OR B) { do something } 

Answer 1

Just use the doublepipe operator, which || .

 if (A || B) 

Answer 2

It is worth noting that || will also return true if BOTH A and B are true .

In JavaScript, if you are looking for A or B , but not both, you need to do something similar to:

 if( (A && !B) || (B && !A) ) { ... } 

Answer 3

Use operator || .

Answer 4

 if (A || B) { do something } 

Answer 5

|| is an or operator.

 if(A || B){ do something } 

Answer 6

here is my example:

 if(userAnswer==="Yes"||"yes"||"YeS"){ console.log("Too Bad!"); } 

This suggests that if the answer is yes or YeS, then the same thing will happen.

Answer 7

Just use ||

 if (A || B) { your action here } 

Note: string and number. This is harder.

Check this one for a deeper understanding:

Answer 8

To use the OR(||) operator if the condition and notation is || More than one condition statement is required. ,

 if(condition || condition){ some stuff } 

Answer 9

You can use as

 if(condition1 || condition2 || condition3 || ..........) { enter code here } 

Answer 10

 if (/A|B/.test(thingToTest)) { doSomething } 

example:

  var myString = "This is my search subject" if (/my/.test(myString)) { doSomethingHere } 

This will look for "my" in the variable "myString". You can replace the string directly instead of the variable "myString".

As an added bonus, you can add to the search case insensitive "i" and global "g".

  var myString = "This is my search subject" if (/my/ig.test(myString)) { doSomethingHere }