Use Yii findAll to return a model with all properties

Question

I'm still new to Yii and wondering how to return JSON from $models = MyModel::model()->findAll(); .

Say, for example, MyModel is relevant for MyChildModels in the ONE: MANY method.

Right from the Rest example on the Yii website, I have:

 foreach ($models as $model) { $rows[] = $model->attributes; } $this->_sendResponse(200, CJSON::encode($rows), 'application/json');

I get all the attributes of the model, but NOT related link attributes.

Similarly, I can change the $rows line:

 $rows[] = $model->myChildModels;

... and I get all MyChildModels attributes for each model, but not any attributes (as you would expect).

But I need a complete set - Model PLUS attributes are all MyChildModels and their attributes.

How to do it?

0

tacos_tacos_tacos Apr 17 '12 at 3:17

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1 answer

jarchuleta · Accepted Answer · 2012-04-17T03:32:14+0000

I do the same with Yii. This is how I do it.

 $models = MyModel::model()->findAll(); if ($models){ echo CJSON::encode($models); }

I usually did not send a JSON header, but you can if you want.

 header('Content-type: application/json');

for related models try this.

 foreach ($models as $model) { $rows[] = $model->attributes; $rows[] = $model->related->attributes; }